Optimal. Leaf size=449 \[ \frac{e^{i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{i d (e+f x)}{f}\right )}{8 a d}-\frac{i 2^{-m-3} e^{2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{3^{-m-1} e^{3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{3 i d (e+f x)}{f}\right )}{8 a d}+\frac{e^{-i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{i d (e+f x)}{f}\right )}{8 a d}+\frac{i 2^{-m-3} e^{-2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{3^{-m-1} e^{-3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{3 i d (e+f x)}{f}\right )}{8 a d}+\frac{(e+f x)^{m+1}}{2 a f (m+1)} \]
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Rubi [A] time = 0.642543, antiderivative size = 449, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 6, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {4523, 3312, 3307, 2181, 4406, 3308} \[ \frac{e^{i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{i d (e+f x)}{f}\right )}{8 a d}-\frac{i 2^{-m-3} e^{2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{3^{-m-1} e^{3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{3 i d (e+f x)}{f}\right )}{8 a d}+\frac{e^{-i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{i d (e+f x)}{f}\right )}{8 a d}+\frac{i 2^{-m-3} e^{-2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{3^{-m-1} e^{-3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{3 i d (e+f x)}{f}\right )}{8 a d}+\frac{(e+f x)^{m+1}}{2 a f (m+1)} \]
Antiderivative was successfully verified.
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Rule 4523
Rule 3312
Rule 3307
Rule 2181
Rule 4406
Rule 3308
Rubi steps
\begin{align*} \int \frac{(e+f x)^m \cos ^4(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{\int (e+f x)^m \cos ^2(c+d x) \, dx}{a}-\frac{\int (e+f x)^m \cos ^2(c+d x) \sin (c+d x) \, dx}{a}\\ &=\frac{\int \left (\frac{1}{2} (e+f x)^m+\frac{1}{2} (e+f x)^m \cos (2 c+2 d x)\right ) \, dx}{a}-\frac{\int \left (\frac{1}{4} (e+f x)^m \sin (c+d x)+\frac{1}{4} (e+f x)^m \sin (3 c+3 d x)\right ) \, dx}{a}\\ &=\frac{(e+f x)^{1+m}}{2 a f (1+m)}-\frac{\int (e+f x)^m \sin (c+d x) \, dx}{4 a}-\frac{\int (e+f x)^m \sin (3 c+3 d x) \, dx}{4 a}+\frac{\int (e+f x)^m \cos (2 c+2 d x) \, dx}{2 a}\\ &=\frac{(e+f x)^{1+m}}{2 a f (1+m)}-\frac{i \int e^{-i (c+d x)} (e+f x)^m \, dx}{8 a}+\frac{i \int e^{i (c+d x)} (e+f x)^m \, dx}{8 a}-\frac{i \int e^{-i (3 c+3 d x)} (e+f x)^m \, dx}{8 a}+\frac{i \int e^{i (3 c+3 d x)} (e+f x)^m \, dx}{8 a}+\frac{\int e^{-i (2 c+2 d x)} (e+f x)^m \, dx}{4 a}+\frac{\int e^{i (2 c+2 d x)} (e+f x)^m \, dx}{4 a}\\ &=\frac{(e+f x)^{1+m}}{2 a f (1+m)}+\frac{e^{i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,-\frac{i d (e+f x)}{f}\right )}{8 a d}+\frac{e^{-i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,\frac{i d (e+f x)}{f}\right )}{8 a d}-\frac{i 2^{-3-m} e^{2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,-\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{i 2^{-3-m} e^{-2 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,\frac{2 i d (e+f x)}{f}\right )}{a d}+\frac{3^{-1-m} e^{3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (-\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,-\frac{3 i d (e+f x)}{f}\right )}{8 a d}+\frac{3^{-1-m} e^{-3 i \left (c-\frac{d e}{f}\right )} (e+f x)^m \left (\frac{i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,\frac{3 i d (e+f x)}{f}\right )}{8 a d}\\ \end{align*}
Mathematica [A] time = 4.71712, size = 405, normalized size = 0.9 \[ \frac{i (e+f x)^m \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^2 \left (-3 i e^{i \left (c-\frac{d e}{f}\right )} \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{i d (e+f x)}{f}\right )-3\ 2^{-m} e^{2 i \left (c-\frac{d e}{f}\right )} \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{2 i d (e+f x)}{f}\right )-i 3^{-m} e^{3 i \left (c-\frac{d e}{f}\right )} \left (-\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,-\frac{3 i d (e+f x)}{f}\right )-3 i e^{-i \left (c-\frac{d e}{f}\right )} \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{i d (e+f x)}{f}\right )+3\ 2^{-m} e^{-2 i \left (c-\frac{d e}{f}\right )} \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{2 i d (e+f x)}{f}\right )-i 3^{-m} e^{-3 i \left (c-\frac{d e}{f}\right )} \left (\frac{i d (e+f x)}{f}\right )^{-m} \text{Gamma}\left (m+1,\frac{3 i d (e+f x)}{f}\right )-\frac{12 i d (e+f x)}{f (m+1)}\right )}{24 a d (\sin (c+d x)+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.199, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( fx+e \right ) ^{m} \left ( \cos \left ( dx+c \right ) \right ) ^{4}}{a+a\sin \left ( dx+c \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}^{m} \cos \left (d x + c\right )^{4}}{a \sin \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.99043, size = 861, normalized size = 1.92 \begin{align*} \frac{{\left (f m + f\right )} e^{\left (-\frac{f m \log \left (\frac{3 i \, d}{f}\right ) - 3 i \, d e + 3 i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{3 i \, d f x + 3 i \, d e}{f}\right ) +{\left (3 i \, f m + 3 i \, f\right )} e^{\left (-\frac{f m \log \left (\frac{2 i \, d}{f}\right ) - 2 i \, d e + 2 i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{2 i \, d f x + 2 i \, d e}{f}\right ) + 3 \,{\left (f m + f\right )} e^{\left (-\frac{f m \log \left (\frac{i \, d}{f}\right ) - i \, d e + i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{i \, d f x + i \, d e}{f}\right ) + 3 \,{\left (f m + f\right )} e^{\left (-\frac{f m \log \left (-\frac{i \, d}{f}\right ) + i \, d e - i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{-i \, d f x - i \, d e}{f}\right ) +{\left (-3 i \, f m - 3 i \, f\right )} e^{\left (-\frac{f m \log \left (-\frac{2 i \, d}{f}\right ) + 2 i \, d e - 2 i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{-2 i \, d f x - 2 i \, d e}{f}\right ) +{\left (f m + f\right )} e^{\left (-\frac{f m \log \left (-\frac{3 i \, d}{f}\right ) + 3 i \, d e - 3 i \, c f}{f}\right )} \Gamma \left (m + 1, \frac{-3 i \, d f x - 3 i \, d e}{f}\right ) + 12 \,{\left (d f x + d e\right )}{\left (f x + e\right )}^{m}}{24 \,{\left (a d f m + a d f\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (f x + e\right )}^{m} \cos \left (d x + c\right )^{4}}{a \sin \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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